C++题解

AC代码

#include <iostream>
#include <algorithm>
using namespace std;

int a[100005];

int main(){
	for(int i = 1; i <= 24; i++){
		cin >> a[i]; 
	}
    int mx = -2147483648, mn = 2147483647;//int的极限
	for (int i = 1; i <= 24; i += 3){
		int ct = max(a[i], max(a[i + 1], a[i + 2])) - min(a[i], min(a[i + 1], a[i + 2]));
		mx = max(mx, ct);
        mn = min(mn, ct);
	}
    cout << mx - mn;

	return 0;
}