简单小模拟

直接判断是否是 c 即可，十分简单

#include<bits/stdc++.h>
using namespace std;
int n,m;
char mapp[2010][2010];
long long ans;
int main(){
	cin>>n>>m;
	for(int i=0;i<=n+1;i++)
		for(int j=0;j<=m+1;j++)
			mapp[i][j]='.';
	for(int i=1;i<=n;i++)
		for(int j=1;j<=m;j++)
			cin>>mapp[i][j];
	for(int i=1;i<=n;i++){
		for(int j=1;j<=m;j++){
			if(mapp[i][j]=='*'&&mapp[i][j-1]=='.'&&mapp[i-1][j]=='.'){
				int hide=1,tall=1,hide2=1;
				for(int k=1;;k++){
					if(mapp[i][j+k]=='*'){
						if(mapp[i+1][j+k]=='.'&&mapp[i-1][j+k]=='.')
							hide++;
					}else break;
				}
				if(mapp[i][j+hide]=='*') continue;
				for(int k=1;;k++){
					if(mapp[i+k][j]=='*'){
						if(mapp[i+k][j+1]=='.'&&mapp[i+k][j-1]=='.')
							tall++;
					}else break;
				}
				if(mapp[i+tall][j-1]=='*') tall--;
				if(mapp[i+tall+1][j]=='*') continue;
				for(int k=1;;k++){
					if(mapp[i+tall][j+k]=='*'){
						if(mapp[i+1+tall][j+k]=='.'&&mapp[i-1+tall][j+k]=='.')
							hide2++;
					}else break;
				}
				if(mapp[i+tall][j+hide2]=='*') continue;
				if(hide2==hide&&hide>=2&&tall>=2){
//					cout<<i<<" "<<j<<" "<<hide<<" "<<hide2<<" "<<tall<<"\n";
					int tmp=0;
					for(int k=1;k<tall;k++){
						for(int t=1;t<hide;t++){
							if(mapp[i+k][j+t]=='*') tmp=1;
						}
					}
					if(tmp==0) ans++;
					tmp=0;
				}
			}
		}
	}
	cout<<ans;
	return 0;
}