题解

#include <bits/stdc++.h>
using namespace std;

int main() {
    vector<int> digits = {1, 2, 3, 4, 5, 6, 7, 8, 9};
    
    do {
        int a_num = digits[0] * 100 + digits[1] * 10 + digits[2];
        int b_num = digits[3] * 100 + digits[4] * 10 + digits[5];
        int c_num = digits[6] * 100 + digits[7] * 10 + digits[8];
        
        if (a_num * 2 == b_num && a_num * 3 == c_num) {
            cout << a_num << " " << b_num << " " << c_num << endl;
        }
    } while (next_permutation(digits.begin(), digits.end()));

    return 0;
}

看题解里面各位大佬都是直接打表，本蒟蒻数学不好，直接硬算了