题解

#include<iostream>
#include<cmath>
using namespace std;
int main(){
int jz,n,a[100],x=0;
cin>>jz>>n;
while(n!=0){
int yu = n%2;
n = n/2;
a[x] = yu;
x++;
}
int cnt=0;
for(int i=0;i<x;i++){
cnt+=pow(jz,i)*a[i];
}
cout<<cnt;
return 0;
}